In this the output sequence X(k) is divided into smaller and smaller sub-sequences , that is why the name Decimation In Frequency. The two important procedures for digitizing the trfer function of an analog filter are: Q13. Decimation-In-Time algorithm is used to calculate the DFT of a N point sequence. Digital Signal Processing (DSP) Viva Questions and Answers ... Viva Questions and Answers on Digital Signal Processing. The test carries questions on DSP Fundamentals, Sampling, Discrete Fourier Transform (DFT), Fast Fourier Transform (FFT), Comparative Analysis of various transforms (Z, Laplace & Fourier), Inverse Z … Solutions have been made available by Tony Jeans for his past papers. What Are Differences Between Overlap-save And Overlap-add Methods? If a b bit register is used the filter coefficients must be rounded or truncated to b bits ,which produces an error. A discrete time system is called static or memory less if its output at any instant n depends almost on the input sample at the same time but not on past and future samples of the input. Q8. How One Can Design Digital Filters From Analog Filters? What Is The Principle Of Designing Fir Filter Using Frequency Sampling Method? If the number of output points N can be expressed as a power of 2 that is N=2M, where M is an integer, then this algorithm is known as radix-2 algorithm. These filters can be easily designed to have perfectly linear phase. Q23. Define Symmetric And Antisymmetric Signal? Unfortunately, they are only available as handwritten notes. We can get better display of the frequency spectrum. If x(n) is a sequence of L number of samples and h(n) with M number of samples, after convolution y(n) will have N=L+M-1 samples. Solution − Taking the Z-transform of the above difference equation, we get, $= H(Z) = \frac{Y(Z)}{X(Z)} = \frac{2}{[1-\frac{1}{2}Z^{-1}]}$, This system has a pole at $Z = \frac{1}{2}$ and $Z = 0$ and $H(Z) = \frac{2}{[1-\frac{1}{2}Z^{-1}]}$, Hence, taking the inverse Z-transform of the above, we get, Determine Y(z),n≥0 in the following case −, $y(n)+\frac{1}{2}y(n-1)-\frac{1}{4}y(n-2) = 0\quad given\quad y(-1) = y(-2) = 1$, Solution − Applying the Z-transform to the above equation, we get, $Y(Z)+\frac{1}{2}[Z^{-1}Y(Z)+Y(-1)]-\frac{1}{4}[Z^{-2}Y(Z)+Z^{-1}Y(-1)+4(-2)] = 0$, $\Rightarrow Y(Z)+\frac{1}{2Z}Y(Z)+\frac{1}{2}-\frac{1}{4Z^2}Y(Z)-\frac{1}{4Z}-\frac{1}{4} = 0$, $\Rightarrow Y(Z)[1+\frac{1}{2Z}-\frac{1}{4Z^2}] =\frac{1}{4Z}-\frac{1}{2}$, $\Rightarrow Y(Z)[\frac{4Z^2+2Z-1}{4Z^2}] = \frac{1-2Z}{4Z}$, $\Rightarrow Y(Z) = \frac{Z(1-2Z)}{4Z^2+2Z-1}$. If X(Z) is anticasual,then ROC includes Z=@. They are fixed point arithmetic, floating point ,block floating point arithmetic. Multiple Choice Questions and Answers on Digital Signal Processing(Part-2) Multiple Choice Questions and Answers By Sasmita December 19, 2016 1) The cost of the digital processors is cheaper because Differentiate between a discrete time signal and a digital signal. Post Views:
Digital Signal Processing Objective Type Questions and Answers for competitive exams. A discrete time signal can be defined as a signal, which is continuous in amplitude and discrete in time. September 2014 Exam . 1.Give the expression for location of poles of normalized Butterworth filter. What Are The Different Types Of Arithmetic In Digital Systems.? Zero padding is necessary to find the response of a filter. What Are The Elementary Discrete Time Signals? Map the desired digital filter specifications into those for an equivalent analog filter. EE8591 - Digital Signal Processing (DSP) Study Materials Download EE8591 - Digital Signal Processing (DSP) Important 2 Marks with Answers Download EE8591 - Digital Signal Processing (DSP) Question Bank Check this page regularly. FIR filters can be realized recursively and non-recursively. Based on impulse response the filters are of two types: The IIR filters are of recursive type, whereby the present output sample depends on the present input, past input samples and output samples. E4810 - Final Exam Solutions 2003-01-05 (corrected 2004-03-05) - page 1/6 E4810 Digital Signal Processing Final Exam - Solutions Exam Date: Thursday 2002-12-19 16:15–18:45 Dan Ellis

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